T.I.M.E. celebrates excellent results in JEE (Main) 2018. As a part of our celebrations at T.I.M.E. we are conducting a T.I.M.E. Admission cum Scholarship Test (ACST) at Hyderabad on 27th of May, 2018 (Sunday). The ACST is open to students who wish to prepare for JEE/NEET 2020. Based on performance, students writing this examination will become eligible for a certain amount of Scholarship on our JEE/NEET 2020 Full Course fee (Terms & Conditions Apply).

The test will contain multiple choice questions on Mathematics, Physics, Chemistry &, Reasoning Ability. The entire test procedure is expected to take 1 hour. A special aspect of this ACST is that every student writing it and enrolling for JEE/NEET 2020 course gets an assured discount. To grab this opportunity and get yourself a minimum discount for JEE/NEET 2020, visit the nearest office of T.I.M.E. latest by 27th of May, 2018, you may also contact us at 040-40088300/400 for more details.

The ACST will be conducted across T.I.M.E. Centres in Hyderabad. You can register for the ACST by filling the form. After you enter the details required, an email of the test venue, timing and hall ticket number will be sent to you. Additionally, the test venue details will be sent through an SMS.

In case you have any further clarifications, please feel free to contact us at hyderabad@time4education.com or call 040-40088400.

Wish you all the best.